0=3(-2)^2+a(-2)-4

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Solution for 0=3(-2)^2+a(-2)-4 equation: 



0=3(-2)^2+a(-2)-4

We move all terms to the left:

0-(3(-2)^2+a(-2)-4)=0

We add all the numbers together, and all the variables

-(3(-2)^2+a(-2)-4)=0



We calculate terms in parentheses: -(3(-2)^2+a(-2)-4), so:

3(-2)^2+a(-2)-4

determiningTheFunctionDomain
a(-2)-4+3(-2)^2

We add all the numbers together, and all the variables

a(-2)+8

We multiply parentheses

-2a+8

Back to the equation:

-(-2a+8)



We get rid of parentheses

2a-8=0

We move all terms containing a to the left, all other terms to the right

2a=8

a=8/2

a=4

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